18x^2+5[6(x^2-2)+5]=0

Solution for 18x^2+5[6(x^2-2)+5]=0 equation:

Simplifying
18x2 + 5[6(x2 + -2) + 5] = 0

Reorder the terms:
18x2 + 5[6(-2 + x2) + 5] = 0
18x2 + 5[(-2 * 6 + x2 * 6) + 5] = 0
18x2 + 5[(-12 + 6x2) + 5] = 0

Reorder the terms:
18x2 + 5[-12 + 5 + 6x2] = 0

Combine like terms: -12 + 5 = -7
18x2 + 5[-7 + 6x2] = 0
18x2 + [-7 * 5 + 6x2 * 5] = 0
18x2 + [-35 + 30x2] = 0

Reorder the terms:
-35 + 18x2 + 30x2 = 0

Combine like terms: 18x2 + 30x2 = 48x2
-35 + 48x2 = 0

Solving
-35 + 48x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '35' to each side of the equation.
-35 + 35 + 48x2 = 0 + 35

Combine like terms: -35 + 35 = 0
0 + 48x2 = 0 + 35
48x2 = 0 + 35

Combine like terms: 0 + 35 = 35
48x2 = 35

Divide each side by '48'.
x2 = 0.7291666667

Simplifying
x2 = 0.7291666667

Take the square root of each side:
x = {-0.853912564, 0.853912564}